lf circular arcs `overline(AC) and overline(BC)` have centres at `B(-alpha, 0) and A(alpha, 0)
511 views · Published 13 October 2018 · 8:59 · Indexed 30 September 2026
Channel: Doubtnut · 2018 · Education
To ask Unlimited Maths doubts download Doubtnut from - https://goo.gl/9WZjCW lf circular arcs `overline(AC) and overline(BC)` have centres at `B(-alpha, 0) and A(alpha, 0)` respectively and equation of circle which touches both arcs `overline(AC) and overline(BC)` and line `AB` is `(x-a)^2+ (y-b)^2=r^2,r gt0,` if length of arc `BC=8pi,` the value of `|a+b+r-alpha|` equals
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