Look Who it Was Random video

CBSE Last Year Maths Question Trigonometry 2

31 views · Published 2 July 2017 · 4:28 · Indexed 20 October 2026

Channel: Dilip Thakur · 2017 · Education

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Prove that   (Cos A-Sin A)/(Cosec A+Sin A)=(〖Sec〗^2 A-〖tan〗^2 A )/(〖Sec〗^2 A+〖tan〗^2 A)
LHS= (Cos A-Sin A)/(Cosec A+Sin A)=(1/SinA-Sin A)/(1/SinA+Sin A)=(1-〖Sin〗^2 A)/(1+〖Sin〗^2 A)=((1-〖Sin〗^2 A)/〖Cos〗^2 A)/((1+〖Sin〗^2 A)/〖Cos〗^2 A)=(〖Sec〗^2 A-〖tan〗^2 A )/(〖Sec〗^2 A+〖tan〗^2 A)=RHS

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