CBSE Last Year Maths Question Trigonometry 2
31 views · Published 2 July 2017 · 4:28 · Indexed 22 September 2026
Channel: Dilip Thakur · 2017 · Education
Prove that (Cos A-Sin A)/(Cosec A+Sin A)=(〖Sec〗^2 A-〖tan〗^2 A )/(〖Sec〗^2 A+〖tan〗^2 A) LHS= (Cos A-Sin A)/(Cosec A+Sin A)=(1/SinA-Sin A)/(1/SinA+Sin A)=(1-〖Sin〗^2 A)/(1+〖Sin〗^2 A)=((1-〖Sin〗^2 A)/〖Cos〗^2 A)/((1+〖Sin〗^2 A)/〖Cos〗^2 A)=(〖Sec〗^2 A-〖tan〗^2 A )/(〖Sec〗^2 A+〖tan〗^2 A)=RHS
